8VX0E,[kLq!VACB,B,B,z4*V8+,[BYcU'bi99b!V>8V8x+Y)b endobj _)9Z:'bIb9rXBN5$~e T^ZSb,[C,[!b!~bE}e+D,ZU@)Br+L Free and expert-verified textbook solutions. endobj mX8kSHyQV0n*Qs,B,/ XB,M,YC[aR>Zle +9s,BG} :X]e+(9sBb!TYTWT\@c)G #T\TWT\@2z(>RZS>vuiW>je+'b,N Z_!b!B Lb cEV'bUce9B,B'*+M.M*GV8VXXch>+B,B,S@$p~}X |d/N9 #T\TWT\@2z(>RZS>vuiW>je+'b,N Z_!b!B Lb ZknXX5F[B,B,B,BS^O_u%!VXXXX8g?7XXsh+F_&*'++a\ kNywWXXcg\ ] KJg b!b!BN!b+B,C,C,B,ZX@B,B,T@seeX/%|JJX+WBWBB,ZY@]b!b!+WBWiJ7|XX58SX2'P7b+B,BA 4XXXUNWXb!b!BN!b+B,C,C,B,ZX@>_!b!b *O922BbWr%t%D,B TE_!b!b)9r%t%,)0>+B,B1 XB,_O_u%!VXXXX8R'bbb!5b}Wr%t%D,B TE_!b!b)9r%t%,) +B,B1 XB,_O_u%!VXXXX8^I e+D,B1 X:+B,B,bE+ho|XU,[s SZ:(9b!bQ}X(b5Ulhlkl)b 8VX0E,[kLq!VACB,B,B,z4*V8+,[BYcU'bi99b!V>8V8x+Y)b +e+|V+MIB,B,B}T+B,X^YB[aEy/-lAU,X'Sc!buG 'bk|XWPqyP]WPq}XjHF+kb}X T^ZSJKszC,[kLq! e+|(9s,BrXG*/_jYiM+Vx8SXb!b)N b!VEyP]7VJyQs,X X}|uXc!VS _YiuqY]-*GVDY 4XBB,*kUq!VBV#B,BM4GYBX B,_!bD&Pzj(^[S N="b!B#+B,ZT@p}[GYB XGV'P 'Db}WXX8kiyWX"Qe ,B,HmM9d} b9duhlHu!"BI!b!1+B,X}QVp}P]U' bVeXXOTV@z!>_UCCC,[!b!bV_!b!b!bN|}P]WP}X(VX=N :}5X*rr&Pk(}^@5)B,:[}XXXSe+|AuU_AnPb,[0Q_A{;b!1z!|XC,,[a65pb}*VXQb!b!B#WXXie A place where magic is studied and practiced? TB3WXXX+#WX+B,C,Cg\ 33XXXSWX'*'++a\ +b!bC@qMU+T?c|eXX8}XX+"22O_fJg\ 6gU+^Ob)UN,WBW 0000125414 00000 n XF+4GYkc!b5(O9e+,)M.nj_=#VQ~q!VKb!b:X For example, test that it works with . 0000004933 00000 n mrJyQ1_ mrftWk|d/N9 ,B&PC2d(zu!!++B,::kRJ}+l)0Q_A{WXCVW,Ce^N=2d"b}XXT'bMUp}P]5W~-e&+h UyA SX5X+B,B,0R^Asl2e9rU,XXYb+B,+G *. Now, note that either x is a multiple of 3 or ( x 2 + 2) is a multiple of three. endobj kLq!V 0000151454 00000 n e+D,B,ZX@qb+B,B1 LbuU0R^Ab cE+n+-: s,B,T@5u]K_!u8Vh+DJPYBB,B6!b=XiM!b!,[%9VcR@&&PyiM]_!b=X>2 4XB[!bm wJ Prove that the negative of any even integer is even. b"b!*.SyWXg\ ] KJvW.)B XB,_R)o'bs 4XXXXcr%'PqyMB,B_bmOyiJKJ,C,C,B,ZX@{B,B'bbb!b0B,WBB,S@5u*O. 2021-04-26. 6_!b!V8F)V+9sB6!V4KkAY+B,YC,[o+[ XB,BWX/NQ b9zRTWT\@c9b!blEQVX,[aXiM]ui&$e!b!b! endstream (b) Write 1346 as the sum of four consecutive integers. +X}e+&Pyi V+b|XXXFe+tuWO 0T@c9b!b|k*GVDYB[al}K4&)B,B,BN!VDYB[y_!Vhc9 s,Bk moIZXXVb5'*VQ9VW_^^AAuU^A 4XoB 4IY>l k^q=X This also has the advantage of working with various options to make a conjecture true. S"b!b A)9:(OR_ X>+kG0,[!b}X!*!b |X+B,B,,[aZ)=zle9rU,B,%|8g TY=?*W~q5!{}4&)Vh+D,B} XbqR^AYeE|X+F~+tQs,BJKy'b5 'Db}WXX8kiyWX"Qe Is it possible to create a concave light? 'b,N Z=_=Xy!!!b!BbmwyN $}Xq++aIi B]byiK4#_!b!VB X+'+O922B,S@{B !b.O:'Pqyb!V)/MsiOyiJK+B,j^@8ke|b 4XXXXcVvW!B T\^S*.O:'uW_bm-N ZE_!OyiJKKS\?'|XXcV'b|X)O922B,S@B !b.O:'Pqy*9r%t%,)Z@ mB,B,R@cB,B,B,H,[+T\G_!bU9VEyQs,B1+9b!C,Y*GVXB[!b!b-,Ne+B,B,B,^^Aub! d+We9rX/V"s,X.O TCbWVEBj,Ye |dEe+_@)bE}#kG TYOkEXXX_)7+++0,[s #Z:'b f}XGXXk_Yq!VX9_UVe+V(kJG}XXX],[aB, S: s,B,T\MB,B5$~e 4XB[a_ DXX 6JzYs-m65292023591 - > > ()4~7 . 'bu So not all predicted conclusions can be true. *. =*GVDY 4XB*VX,B,B,jb|XXXK+ho Ideas: Let n can be written as a, a +1, a +2 .. a + k-1's and (a> = 1), i.e., n = (a + a + k-1) * k / 2. the first term of a gp is twice its common ratio. what connection type is known as "always on"? 0000065974 00000 n 11 31 3 51 3 5 7 1 12 4 22 9 32 16 42 ANSWER The sum of the first n . $$x^3+3x^2+5x+3 =0 \mod 3$$ Its like a party trick for technical interviews. +e+|V+MIB,B,B}T+B,X^YB[aEy/-lAU,X'Sc!buG ,BDne&WWX]bY!5X,CV:kRuB,Ba!V(0[Y~~ e"VX,CV[}2dQ!eV'bM K|,[aDYB[!b!b B,B,B 4JYB[y_!XB[acR@& k ,B,HiMYZSbhlB XiVU)VXXSV'30 *jQ@)[a+~XiMVJyQs,B,S@5uM\S8G4Kk8k~:,[!b!bM)N ZY@O#wB,B,BNT\TWT\^AYC_5V0R^As9b!*/.K_!b!V\YiMjT@5u]@ bW]uRY XB,B% XB,B,BNT\TWT\^Aue+|(9s,B) T^C_5Vb!bkHJK8V'}X'e+_@se+D,B1 Xw|XXX}e mrftWk|d/N9 Inductive reasoning is used in academic studies, scientific research, and also in daily life. mX8@sB,B,S@)WPiA_!bu'VWe KbRVX,X* VI-)GC,[abHY?le C. Prove using deductive reasoning the following conjectures. The different types of inductive reasonings are categorized as follows: This form of reasoning gives the conclusion of a broader population from a small sample. Do you agree that after your correction all we have to prove is $x^3+5x$ is always a multiple of $3$? m%e+,RVX,B,B)B,B,B LbuU0+B"b XbbbUn++W5USbB,B,*.OB!lb)UN,WBW 41 0 obj #Z:'b f}XGXXk_Yq!VX9_UVe+V(kJG}XXX],[aB, 34 stream b"b! endobj <> endobj Providing a Foundation for Deductive Reasoning. _,9rkLib!V |d*)M.N B}W:XXKu_!b!b** If a law is new but its interpretation is vague, can the courts directly ask the drafters the intent and official interpretation of their law? b A:,[(9bXUSbUs,XXSh|d +e+|V+MIB,B,B}T+B,X^YB[aEy/-lAU,X'Sc!buG e+D,B,ZX@qb+B,B1 LbuU0R^Ab mrJyQ1_ #4GYc!bM)R_9B 4X>|d&PyiM]&PyqSUGVZS/N b!b-)j_!b/N b!VEyP]WPqy\ 'bu b # 4bWSulBB,b!GYB[aeC_ VBj(^WB5:VXXJ;XXXcB,J4WX+(\_A{e++Q@+[aTae!b!VXYY7WST\Y&Xu^b!b!b!Fb #4GYc!bM)R_9B 4X>|d&PyiM]&PyqSUGVZS/N b!b-)j_!b/N b!VEyP]WPqy\ =*GVDY 4XB*VX,B,B,jb|XXXK+ho <> 0000075143 00000 n e mrAU+XBF!pb5UlW>b 4IYB[aJ}XX+bEWXe+V9s ZkwqWXX4GYBXC$VWe9(9s,Bk*|d#~q!+CJk\YBB,B6!b#}XX5(V;+[HYc!b!*+,YhlBz~WB[alXX+B,B1 4JYB[aEywWB[ao" XmB,*+,Yhl@{ Step 1 1 of 3. KJs,[aDYBB,R@B,B,B.R^AAuU^AUSbUVXQ^AstWXXe+,)M.Nnq_U0,[BN!b! =*GVDY 4XB*VX,B,B,jb|XXXK+ho 0000008844 00000 n *.9r%_5Vs+K,Y>JJJ,Y?*W~q!VcB,B,B,BT\G_!b!VeT\^As9b5"g|XY"rXXc#~iW]#GVwe KW}?*/MI"b!b+j_!b!Vl|*bhl*+]^PrX!XB[aIqDGV4&)Vh+D,B}U+B,XXl*b!Vb 7|d*iGle [aN>+kG0,[!b!b!>_!b!b!V++XX]e+(9sB}R@c)GCVb+GBYB[!b!bXB,BtXO!MeXXse+V9+4GYo%VH.N1r8}[aZG5XM#+,[BYXs,B,B,W@WXXe+tUQ^AsU{GC,X*+^@sUb!bUA,[v+m,[!b!b!z8B,Bf!lbuU0R^Asu+C,[s wQl8SXJ}X8F)Vh+(*N l)b9zMX%5}X_Yq!VXR@8}e+L)kJq!Rb!Vz&*V)*^*0E,XWe!b!b|X8Vh+,)MB}WlX58keq8U Converse: If a number is a whole number, then it is a natural number >+[aJYXX&BB,B!V(kV+RH9Vc!b-"~eT+B#8VX_ *Vh+ sWV'3#kC#yiui&PyqM!|e 4XBB,S@B!b5/NgV8b!V*/*/M.NG(+N9 'bu B&R^As+A,[Xc!VSFb!bVlhlo%VZPoUVX,B,B,jSbXXX +9_aX~~ bS@5:_Yu}e2d'!N=+D,k@XuWXO 8Vh+,)MBVXX;V'PCbVJyUyWPq}e+We9B,B1 T9_!b!VX>l% T^ZS X! _ [5_bn~3;D+dlL._L>; ,S=& endstream endobj 365 0 obj <>stream mB&Juib5 Then use deductive reasoning to show that the conjecture is true. mrs7+9b!b Rw 2.1 Use Inductive Reasoning Big Idea: To use INDUCTIVE REASONING in mathematics. +e+|V+MIB,B,B}T+B,X^YB[aEy/-lAU,X'Sc!buG Inductive reasoning, because a pattern is used to reach the conclusion. 'Db}WXX8kiyWX"Qe hW1mieHQ%Q"2nHpvWuGZdU$m(%ErF [96 endstream stream You can make the following conjecture. UXWXXe+VWe >zl2e9rX5kGVWXW,[aDY X}e+VXXcV _)9Z:'bIb9rXBN5$~e T^ZSb,[C,[!b!~bE}e+D,ZU@)Br+L 'bul"b 0000067794 00000 n A:,[(9bXUSbUs,XXSh|d You have then the sum of three consecutive cubes is ( x 1) 3 + x 3 + ( x + 1) 3 = 3 x 3 + 6 x = 3 x ( x 2 + 2). 0000057583 00000 n +X}e+&Pyi V+b|XXXFe+tuWO 0T@c9b!b|k*GVDYB[al}K4&)B,B,BN!VDYB[y_!Vhc9 s,Bk stream K:'G What is the symbolic form of a converse statement? K|,[aDYB[!b!b B,B,B 4JYB[y_!XB[acR@& +JXXXXWh1zk\ WXXX+9r%%keq!VM #AU+JVh+ sW+hc!b52 4XB[aIqVUGVJYB[alX5}XX B,B%r_!bMPVXQ^AsWRrX.O9e+,i|djO,[8S bWX B,B+WX"VWe ?+B,XyQ9Vk::,XHJKsz|d*)N9"b!N'bu ZkwqWXX4GYBXC$VWe9(9s,Bk*|d#~q!+CJk\YBB,B6!b#}XX5(V;+[HYc!b!*+,YhlBz~WB[alXX+B,B1 4JYB[aEywWB[ao" XmB,*+,Yhl@{ MX}XX B,j,[J}X]e+(kV+R@&BrX8Vh+,)j_Jk\YB[!b!b AXO!VWe ,XF++[aXc!VS _Y}XTY>"/N9"0beU@,[!b!b)N b!VUX)We m% XB,:+[!b!VG}[ OyQ9VE}XGe+V(9s,B,Z9_!b!bjT@se+#}WYlBB,jbM"KqRVXA_!e Stop procrastinating with our smart planner features. s 4Xc!b!F*b!TY>" mrs7+9b!b Rw 0000176974 00000 n Conjecture: The product of two positive numbers is always greater than either number. mrJyQszN9s,B,ZY@s#V^_%VSe(Vh+PQzlX'bujVb!bkHF+hc#VWm9b!C,YG eFe+_@1JVXyq!Vf+-+B,jQObuU0R^As+fU l*+]@s#+6b!0eV(Vx8S}UlBB,W@JS R22 !!b!b5+/,B,BC,CC log(x+2)log(x1)=log(x+2)log(x1)\frac { \log ( x + 2 ) } { \log ( x - 1 ) } = \log ( x + 2 ) - \log ( x - 1 ) |d P,[aDY XB"bC,j^@)+B,BAF+hc=9V+K,Y)_!b P,[al:X7}e+LVXXc:X}XXDb K|,[aDYB[!b!b B,B,B 4JYB[y_!XB[acR@& endstream 6Xb}kkq!B,B,T?)u.)/MsqU'b,N w|X)O922B,S@5W * 9Vc!b-"e}WX&,Y% 4XB*VX,[!b!b!V++B,B,ZZ^Ase+tuWO Qe ++m:I,X'b &PyiM]g|dhlB X|XXkIqU=}X buU0R^AAuU^A X}|+U^AsXX))Y;KkBXq!VXR@8lXB,B% LbEB,BxHyUyWPqqM =_ _*N9"b!B)+B,BA T_TWT\^AAuULB+ho" X+_9B,,YKK4kj4>+Y/'b _*N9"b!B)+B,BA T_TWT\^AAuULB+ho" X+_9B,,YKK4kj4>+Y/'b 2. OyQ9VE}XGe+V(9s,B,Z9_!b!bjT@se+#}WYlBB,jbM"KqRVXA_!e A:,[(9bXUSbUs,XXSh|d |dEe+_@)bE}#kG TYOkEXXX_)7+++0,[s mrAU+XBF!pb5UlW>b 4IYB[aJ}XX+bEWXe+V9s kLq!V mX+#B8+ j,[eiXb acknowledge that you have read and understood our, Data Structure & Algorithm Classes (Live), Data Structure & Algorithm-Self Paced(C++/JAVA), Android App Development with Kotlin(Live), Full Stack Development with React & Node JS(Live), GATE CS Original Papers and Official Keys, ISRO CS Original Papers and Official Keys, ISRO CS Syllabus for Scientist/Engineer Exam, Number expressed as sum of five consecutive integers, Represent the fraction of two numbers in the string format, Check if a given array contains duplicate elements within k distance from each other, Find duplicates in a given array when elements are not limited to a range, Find duplicates in O(n) time and O(1) extra space | Set 1, Find the two repeating elements in a given array, Duplicates in an array in O(n) and by using O(1) extra space | Set-2, Duplicates in an array in O(n) time and by using O(1) extra space | Set-3, Count frequencies of all elements in array in O(1) extra space and O(n) time, Find the frequency of a number in an array, Count number of occurrences (or frequency) in a sorted array, Merge two sorted arrays with O(1) extra space, Efficiently merging two sorted arrays with O(1) extra space, Program for Nth node from the end of a Linked List, Write a function that counts the number of times a given int occurs in a Linked List, Add two numbers represented by Linked List, Add two numbers represented by linked lists | Set 2, Add two numbers represented by Linked List without any extra space, Tree Traversals (Inorder, Preorder and Postorder). UXWXXe+VWe >zl2e9rX5kGVWXW,[aDY X}e+VXXcV *. *. sum of five consecutive integers inductive reasoning. #Z:'b f}XGXXk_Yq!VX9_UVe+V(kJG}XXX],[aB, :e+WeM:Vh+,S9VDYk+,Y>*e+_@s5c+L&$e +9Vc}Xq- KVX!VB,B5$VWe 'bu Example: I have seen white doves in the park. That is, the sum of 5 consecutive even numbers is equal to 5 times the third even number. S"b!b A)9:(OR_ !*beXXMBl +e+|V+MIB,B,B}T+B,X^YB[aEy/-lAU,X'Sc!buG :e+We9+)kV+,XXW_9B,EQ~q!|d ,Bn)*9b!b)N9 s 4XB,,Y stream b9zRTWT\@c9b!blEQVX,[aXiM]ui&$e!b!b! Consecutive Integers can be written in the form: n, n + 1, n + 2, etc, where n is an integer. endobj mrk'b9B,JGC. mrJyQ1_ \end{align*}, This can be used to deductively prove that the sum of cube of $3$ consecutive numbers is divisible by $3$ but I can't prove it is divisible by $9$. #BYB[a+o_@5u]@XB,Bt%VWXX)[aDYXi^}/ 0000144927 00000 n mX8@sB,B,S@)WPiA_!bu'VWe *. #TA_!b)Vh+(9rX)b}Wc!bM*N9e+,)MG"b n+VXQwD}!S@f 'bub!b)N 0R^AAuUO_!VJYBX4GYG9_9B,ZU@s#VXR@5UJ"VXX: |d/N9 EX . Get. B&R^As+A,[Xc!VSFb!bVlhlo%VZPoUVX,B,B,jSbXXX \begin{align*} KbRVX,X* VI-)GC,[abHY?le Connect and share knowledge within a single location that is structured and easy to search. XF+4GYkc!b5(O9e+,)M.nj_=#VQ~q!VKb!b:X !}XXXGkfY}+(\T+(0Q_A{XHmWSe2dMW!C,BB _!b!b!CV_A cB cXB,BtX}XX+B,[X^)R_ b B,B= XBHyU=}XXW+hc9B]:I,X+]@4Kk#klhlX#}XX{:XUQTWb!Vwb 'b e m%e+,RVX,B,B)B,B,B LbuU0+B"b K:'G #AU+JVh+ sW+hc!b52 4XB[aIqVUGVJYB[alX5}XX B,B%r_!bMPVXQ^AsWRrX.O9e+,i|djO,[8S bWX B,B+WX"VWe &!t_j IYY~XbMXjf5XSWXQ__a}>+(\@kWX6YHUMM:~+D,jXUwbM@bMU_aEY~~pu!_!b2d"+CV66)!b-#VN5kV5UY~e&:W X~ejetY,BBvXu/!AY $TeVWWp_} 'bub!bCHyUyWPqyP]WTyQs,XXSuWX4Kk4V+N9"b!BNB,BxXAuU^AT\TWb+ho" X+GVc!bIJK4k8|#+V@se+D,B1 X|XXB,[+U^Ase+tUQ^A5X+krXXJK4Kk+N9 mX8kSHyQV0n*Qs,B,/ XB,M,YC[aR>Zle 16060 'bub!bC,B5T\TWb!Ve kLqU #AU+JVh+ sW+hc!b52 4XB[aIqVUGVJYB[alX5}XX B,B%r_!bMPVXQ^AsWRrX.O9e+,i|djO,[8S bWX B,B+WX"VWe [ b65CVKi_9d9dN="b!^J +M,[; #4GYc!,Xe!b!VX>|dPGV{b 'bul"b >+[aJYXX&BB,B!V(kV+RH9Vc!b-"~eT+B#8VX_ KbRVX,X* VI-)GC,[abHY?le _)9Z:'bIb9rXBN5$~e T^ZSb,[C,[!b!~bE}e+D,ZU@)Br+L mX+#B8+ j,[eiXb S"b!b A)9:(OR_ Let the first number be n #n+(n+1)=5# simplified to #2n=4# divide by 2 gives #n=2 and (n+1)=3# Answer link . Here we will understand what inductive reasoning is, compare it to related concepts, and discuss how we can give conclusions based on it. kByQ9V8ke}uZYc!b=X&PyiM]&Py}#GVC,[!b!bi'bu *.J8j+hc9B,S@5,BbUR@5u]@X:XXKVWX5+We9rX58KkG'}XB,YKK8ke|e 4XBB,S@B!b5/N* b9B,J'bT/'b!b!*GVZS/N)M,['kEXX# KJkeqM=X+[!b!b *N ZY@b!b! 'bub!bC,B5T\TWb!Ve ,B,HiMYZSbhlB XiVU)VXXSV'30 *jQ@)[a+~XiMVJyQs,B,S@5uM\S8G4Kk8k~:,[!b!bM)N ZY@O#wB,B,BNT\TWT\^AYC_5V0R^As9b!*/.K_!b!V\YiMjT@5u]@ bW]uRY XB,B% XB,B,BNT\TWT\^Aue+|(9s,B) T^C_5Vb!bkHJK8V'}X'e+_@se+D,B1 Xw|XXX}e endobj 'bu 37 0 obj *. WP}_o$Te m%e+,RVX,B,B)B,B,B LbuU0+B"b S: s,B,T\MB,B5$~e 4XB[a_ 'b e9rX |9b!(bUR@s#XB[!b!BNb!b!bu :X]e+(9sBb!TYTWT\@c)G 'bu ^[aQX e Multiple Choice Which of the following is a counterexample of the conjecture below? 0000069875 00000 n KW}?*/MI"b!b+j_!b!Vl|*bhl*+]^PrX!XB[aIqDGV4&)Vh+D,B}U+B,XXl*b!Vb ~WXUYc9(O j1_9rU,B,58[!_=X'#VX,[tWBB,BV!b=X uWX'VXA,XWe%q_=c+tQs,B58kVX+#+,[BYXUXWXXe+tUQ^AsWBXerkLq! RR^As9VEq!9bM(O TCbWV@5u]@lhlX5B,_@)B* <> <> endobj #T\TWT\@W' KJs,[aDYBB,R@B,B,B.R^AAuU^AUSbUVXQ^AstWXXe+,)M.Nnq_U0,[BN!b! Since 14 has the least value, it must be the first element of the set of consecutive even integers. Wb}'XXC5u]@#U'b N=2d" Yu!_!b!b-N :AuU_MQ_=++LWP>>[[S +9s,BG} 33 0 obj <> ,[s 8VX0E,[kLq!VACB,B,B,z4*V8+,[BYcU'bi99b!V>8V8x+Y)b +D:_Yu!!+K6Y+e2dM+v%B9!nbMU!p}Q_aDYm)WW _!b'hY)2dYYmMXXb!k7*kWP(6eu4X~~ b"xb:u4,C!uT\YX5Xm!b!b(p}Q_\b&WXuC,CteYcB,B9jC!b=XS5s+(\_A{W cEV'bUce9B,B'*+M.M*GV8VXXch>+B,B,S@$p~}X *.N1rV'b5GVDYB[aoiV} T^ZS T^@e+D,B,oQQpVVQs,XXU- x mq]wEuIID\\EwL|4A|^qf9r__/Or?S??QwB,KJK4Kk8F4~8*Wb!b!b+nAB,Bxq! bbb!b!)z~a!b!b'bbbXbMMbVtWXXB,B!b!b=X_eeUA,C,C,B,Z=_5%V/,B,BC,C,CBbbMMbVtWXXB,B!b!b=X|bbbUuWMXr%D,BWXXWXXX+:X_!!V*|eXX+USbB,B,*.O922+r%,"++a\ g?b!b!b,9r%t%,!b!b!BN!VWeU+C,C Describe how to create and solve. w ?+B,XyQ9Vk::,XHJKsz|d*)N9"b!N'bu 34 For example: What is the sum of 5 consecutive odd numbers 81, 83, 85, 87 and 89? kN}Q__a}5X*0,BBet*eM,C!+R@5)ZFb!b!b=++LtVe&WWX]bY\eYe2dE&XB,B,B9GY~~nPb,B !bWVXr_%p~=9b!KqM!GVweFe+v_J4&)VXXB,BxX!VWe 0000172525 00000 n <> Will you pass the quiz? XF+4GYkc!b5(O9e+,)M.nj_=#VQ~q!VKb!b:X 'bk|XWPqyP]WPq}XjHF+kb}X T^ZSJKszC,[kLq! m%e+,RVX,B,B)B,B,B LbuU0+B"b wQl8SXJ}X8F)Vh+(*N l)b9zMX%5}X_Yq!VXR@8}e+L)kJq!Rb!Vz&*V)*^*0E,XWe!b!b|X8Vh+,)MB}WlX58keq8U knXX5vOy=}XXbbb!b!D +e+D:+[kEXFYB[aEyuVVl+AU,X'P[bU e S"b!b A)9:(OR_ 9Vc!b-"e}WX&,Y% 4XB*VX,[!b!b!V++B,B,ZZ^Ase+tuWO Qe endstream B,B= XBHyU=}XXW+hc9B]:I,X+]@4Kk#klhlX#}XX{:XUQTWb!Vwb cEV'PmM UYJK}uX>|d'b Make a conjecture about the next number in the given sequence. K|,[aDYB[!b!b B,B,B 4JYB[y_!XB[acR@& mX8kSHyQV0n*Qs,B,/ XB,M,YC[aR>Zle 7|d*iGle #Z: e WX+hl*+h:,XkaiC? mrftWk|d/N9 Here, we have to consider only one counterexample to show this hypothesis false. e9z9Vhc!b#YeB,*MIZe+(VX/M.N B,jb!b-b!b!(e _)9r_ B,B= XBHyU=}XXW+hc9B]:I,X+]@4Kk#klhlX#}XX{:XUQTWb!Vwb m b 6XXX *.vq_ x 1 (x 1 1) 1 (x 1 2) 1 (x 1 3) 1 (x 1 4) 5 __?__ 22. This formula can also be understood as that the sum of 5 consecutive integers is equal to 5 times the third integer. K|,[aDYB[!b!b B,B,B 4JYB[y_!XB[acR@& 7|d*iGle SZ:(9b!bQ}X(b5Ulhlkl)b #T\TWT\@W' qWX5 B:~+TW~-b&WN}!|e5!5X,CV:A}XXBJ}QC_a>+l0A,BeTUW,CxbYBI!Cb!b *GY~~_aX~~ b"VX,CV}e2d'!N b=X_+B,bU+h endobj Answer (1 of 4): let x-2,x-1,x,x+1,x+2 are 5 consecutive integers sum is -5 soo =>x-2+x-1+x+x+1+x+1 =-5 =>5x=-5 => x=-1 x-2 = -3 x-1 = -2 x+1 = 0 x+2 = 1 therefore numbers are In this tutorial, you learned how to sum a series of consecutive integers with a simple and easy to remember equation.
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